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BinaryTree Count Not Equal

Geoffrey Challen // 2021.5.0

Create a method countNotEqual that accepts a BinaryTree<Int>? and an Int and returns a count of the number of nodes in the tree that contain a value not equal to the passed value. If the passed tree is null you should return 0.

For reference, cs125.trees.BinaryTree<T> is defined like this:

As a result, tree.value is an Int which you can compare to the passed value in the usual way.