Let's implement a classic algorithm: binary search on an array.

Implement a class named BinarySearcher that provides one static method named search. search takes a SearchList as its first parameter and an int as its second. If the SearchList is null or empty, you should throw an IllegalArgumentException.

SearchList is a provided class. It provides a get(int) method that returns the int at that index, and a size method that returns the size of the SearchList. Those are the only two methods you should need!

search returns a boolean indicating whether the passed value is located in the sorted SearchList. To search the sorted SearchList efficiently, implement the following algorithm:

• Examine the value in the middle of the current array (index (start + end) / 2)
• If the midpoint value is the value that we are looking for, return true
• If the value that we are looking for is greater than the midpoint value, adjust the current array to start at the midpoint
• if the value that we are looking for is less than the midpoint value, adjust the current array to end at the midpoint
• Continue until you find the value, or until the start reaches the end, at which point you can give up and return false

This is a fun problem! Good luck! Keep in mind that every time you call SearchList.get that counts as one access, so you'll need to reduce unnecessary accesses to pass the test suite. Specifically, you should only call list.get once per iteration, saving the result into a temporary variable.